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0 0 1 1 1 0 0 1 1 
0 1 0 0 1 1 NO-TRACE-STRING                                                0 0 0 0 0
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0 1 1 21 15 0 0 3 
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.CMD SET TOL 0.001000000000000
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.CMD DEFINE_FONTSTYLE_NAME fontID=2 name=Text
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.CMD DEFINE_FONTSTYLE_NAME fontID=5 name=User^2
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.CMD DEFINE_FONTSTYLE_NAME fontID=9 name=User^6
.CMD DEFINE_FONTSTYLE_NAME fontID=10 name=User^7
.CMD DEFINE_FONTSTYLE fontID=0 family=Times^New^Roman points=10 bold=0 italic=0 underline=0 colrid=-1
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Файл для студентов}}
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\b Лабораторная работа 2\par Решение нелинейных уравнений\par ПРИМЕР  
РЕШЕНИЯ ЗАДАЧИ 2.1  ВАРИАНТ 0}}
.EQN 11 -3 882 0 0 0
{0:f}NAME({0:x}NAME):(({0:cos}NAME({0:x}NAME)))^(2)-({0:cos}NAME({0:x}NAME))/(12)-(1)/(24)
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{0:x}NAME:0,0+0.1;3
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\plain\s0\f0\fs20 \pard {\cf1\f1 Отрезки  локализации\par [1,1.5],   [1.5,2]}{
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Cg a68.500000,68.500000,14
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\b Метод бисекции}}
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{0:bisec}NAME({0:f}NAME,{0:a}NAME,{0:b}NAME,{0:\e}NAME):((((((({0:an}NAME){72}({0:a}NAME)){71}(({0:bn}NAME){72}({0:b}NAME))){71}(({0:k}NAME){72}(0))){71}((((((((({0:xn}NAME){72}(({0:an}NAME+{0:bn}NAME)/(2))){71}(({0:fa}NAME){72}({0:f}NAME(
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\b ПЕРВЫЙ  КОРЕНЬ}}
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\b - значение  корня\par - число итераций}}
.EQN 1 -33 906 0 0 0
{0:bisec}NAME({0:f}NAME,1,1.5,(10)^(-10))={0}?_n_u_l_l_
.TXT 14 -2 907 0 0 0
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Встроенная функция пакета MATHCAD}}
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{0:x0}NAME:1
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задание начального  приближения}}
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Значение  корня отличается от найденного с помощью функции bisec, так 
как по умолчанию величина погрешности при работе встроенных функций 
равна 0.001}}
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Переопределим параметр  для задания  погрешности}{\cf1\f1  }}
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{0:TOL}NAME:(10)^(-10)
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\b ВТОРОЙ  КОРЕНЬ}}
.EQN 6 -1 896 0 0 0
{0:bisec}NAME({0:f}NAME,1.5,2,(10)^(-10))={0}?_n_u_l_l_
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{0:x0}NAME:1.8
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{0:root}NAME({0:f}NAME({0:x0}NAME),{0:x0}NAME)={0}?_n_u_l_l_
